Q1) \(x + 7\over 5\) + \(x + 6\over 5\) = \(2 x + 13\over 5\)
Q1) \(10\over x+ 9\) - \(8\over x +5\) = \(2 x -22\over x^{2}+ 14 x +45 \)
Q1) \(3\over x+ 2\) + \(6\over x +5\) = \(9 x + 27\over x^{2}+7x +10 \)
Q2) \(x + 5\over 2\) - \(x + 6\over 5\) = \(3 x + 13\over 10\)
Q2) \(8\over x+ 3\) - \(4\over x +3\) = \(4 x + 12\over x^{2}+ 6 x +9 \)
Q2) \(9\over x+ 2\) - \(5\over x +3\) = \(4 x + 17\over x^{2}+5x +6 \)
Q3) \(x + 7\over 3\) - \(x + 9\over 8\) = \(5 x + 29\over 24\)
Q3) \(9\over x+ 8\) - \(6\over x +3\) = \(3 x -21\over x^{2}+ 11x +24 \)
Q3) \(8\over x+ 6\) - \(5\over x +4\) = \(3 x + 2\over x^{2}+10x +24 \)
Q4) \(x + 7\over 5\) - \(x + 8\over 7\) = \(2 x + 9\over 35\)
Q4) \(9\over x+ 3\) - \(3\over x +2\) = \(6 x + 9\over x^{2}+ 5 x +6 \)
Q4) \(8\over x+ 6\) - \(5\over x -3\) = \(3 x -54\over x^{2}+3x -18 \)
Q5) \(x + 8\over 2\) + \(x + 4\over 3\) = \(5 x + 32\over 6\)
Q5) \(10\over x+ 6\) - \(7\over x +4\) = \(3 x -2\over x^{2}+ 10 x +24 \)
Q5) \(5\over x+ 3\) + \(9\over x +7\) = \(14 x + 62\over x^{2}+10x +21 \)
Q6) \(x + 7\over 3\) + \(x + 5\over 3\) = \(2 x + 12\over 3\)
Q6) \(9\over x+ 6\) + \(6\over x +4\) = \(15 x + 72\over x^{2}+ 10 x +24 \)
Q6) \(9\over x+ 6\) - \(3\over x -8\) = \(6 x -90\over x^{2}-2x -48 \)
Q7) \(x + 8\over 3\) - \(x + 8\over 7\) = \(4 x + 32\over 21\)
Q7) \(10\over x+ 2\) - \(5\over x +2\) = \(5 x + 10\over x^{2}+ 4 x +4 \)
Q7) \(9\over x+ 3\) - \(6\over x -10\) = \(3 x -108\over x^{2}-7x -30 \)
Q8) \(x + 9\over 4\) - \(x + 9\over 7\) = \(3 x + 27\over 28\)
Q8) \(10\over x+ 5\) + \(9\over x +8\) = \(19 x + 125\over x^{2}+ 13 x +40 \)
Q8) \(7\over x+ 3\) - \(4\over x -3\) = \(3 x -33\over x^{2} -9 \)
Q9) \(x + 8\over 2\) - \(x + 9\over 6\) = \(2 x + 15\over 6\)
Q9) \(9\over x+ 2\) - \(6\over x +3\) = \(3 x + 15\over x^{2}+ 5 x +6 \)
Q9) \(10\over x+ 2\) + \(7\over x -8\) = \(17 x -66\over x^{2}-6x -16 \)
Q10) \(x + 4\over 3\) - \(x + 9\over 5\) = \(2 x -7\over 15\)
Q10) \(10\over x+ 8\) + \(4\over x +2\) = \(14 x + 52\over x^{2}+ 10 x +16 \)
Q10) \(8\over x+ 5\) - \(6\over x +5\) = \(2 x + 10\over x^{2}+10x +25 \)